Base | Representation |
---|---|
bin | 10011000100001000001… |
… | …010100001000110010111 |
3 | 11122020121021001020002011 |
4 | 103010020022201012113 |
5 | 132431042103000043 |
6 | 2441504052325051 |
7 | 163436356155445 |
oct | 23041012410627 |
9 | 4566537036064 |
10 | 1310102000023 |
11 | 46567a474343 |
12 | 191aa6613787 |
13 | 96707c7884b |
14 | 475a309db95 |
15 | 2412ac3059d |
hex | 131082a1197 |
1310102000023 has 2 divisors, whose sum is σ = 1310102000024. Its totient is φ = 1310102000022.
The previous prime is 1310101999991. The next prime is 1310102000047. The reversal of 1310102000023 is 3200002010131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310102000023 - 25 = 1310101999991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310101999967 and 1310102000012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310102000723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655051000011 + 655051000012.
It is an arithmetic number, because the mean of its divisors is an integer number (655051000012).
Almost surely, 21310102000023 is an apocalyptic number.
1310102000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310102000023 is an equidigital number, since it uses as much as digits as its factorization.
1310102000023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 1310102000023 its reverse (3200002010131), we get a palindrome (4510104010154).
The spelling of 1310102000023 in words is "one trillion, three hundred ten billion, one hundred two million, twenty-three", and thus it is an aban number.
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