Base | Representation |
---|---|
bin | 10011000100001000001… |
… | …010100001011001000111 |
3 | 11122020121021001021201121 |
4 | 103010020022201121013 |
5 | 132431042103014343 |
6 | 2441504052334411 |
7 | 163436356162111 |
oct | 23041012413107 |
9 | 4566537037647 |
10 | 1310102001223 |
11 | 46567a475234 |
12 | 191aa6614407 |
13 | 96707c79262 |
14 | 475a30a03b1 |
15 | 2412ac30aed |
hex | 131082a1647 |
1310102001223 has 2 divisors, whose sum is σ = 1310102001224. Its totient is φ = 1310102001222.
The previous prime is 1310102001209. The next prime is 1310102001293. The reversal of 1310102001223 is 3221002010131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310102001223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310102001197 and 1310102001206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310102001293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655051000611 + 655051000612.
It is an arithmetic number, because the mean of its divisors is an integer number (655051000612).
Almost surely, 21310102001223 is an apocalyptic number.
1310102001223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310102001223 is an equidigital number, since it uses as much as digits as its factorization.
1310102001223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1310102001223 its reverse (3221002010131), we get a palindrome (4531104011354).
The spelling of 1310102001223 in words is "one trillion, three hundred ten billion, one hundred two million, one thousand, two hundred twenty-three".
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