1310102513581 has 2 divisors, whose sum is σ = 1310102513582. Its totient is φ = 1310102513580.

The previous prime is 1310102513569. The next prime is 1310102513627. The reversal of 1310102513581 is 1853152010131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1279228860900 + 30873652681 = 1131030^2 + 175709^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310102513581 - 2¹³ = 1310102505389 is a prime.

It is a super-2 number, since 2×1310102513581² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310102513281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655051256790 + 655051256791.

It is an arithmetic number, because the mean of its divisors is an integer number (655051256791).

Almost surely, 2^{1310102513581} is an apocalyptic number.

It is an amenable number.

1310102513581 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310102513581 is an equidigital number, since it uses as much as digits as its factorization.

1310102513581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 31.

The spelling of 1310102513581 in words is "one trillion, three hundred ten billion, one hundred two million, five hundred thirteen thousand, five hundred eighty-one".