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131010310100011 is a prime number
BaseRepresentation
bin11101110010011100110110…
…111111101101010000101011
3122011212110111202201001121211
4131302130312333231100223
5114132433103341200021
61142345150001413551
736411116420646226
oct3562346677552053
9564773452631554
10131010310100011
113882018468a931
121283a81393a2b7
1358142b0864204
14244cd0ba0a5bd
151022d2b0243e1
hex772736fed42b

131010310100011 has 2 divisors, whose sum is σ = 131010310100012. Its totient is φ = 131010310100010.

The previous prime is 131010310099969. The next prime is 131010310100053. The reversal of 131010310100011 is 110001013010131.

It is a balanced prime because it is at equal distance from previous prime (131010310099969) and next prime (131010310100053).

It is a cyclic number.

It is not a de Polignac number, because 131010310100011 - 27 = 131010310099883 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131010310099964 and 131010310100000.

It is not a weakly prime, because it can be changed into another prime (131010310110011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505155050005 + 65505155050006.

It is an arithmetic number, because the mean of its divisors is an integer number (65505155050006).

Almost surely, 2131010310100011 is an apocalyptic number.

131010310100011 is a deficient number, since it is larger than the sum of its proper divisors (1).

131010310100011 is an equidigital number, since it uses as much as digits as its factorization.

131010310100011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 131010310100011 its reverse (110001013010131), we get a palindrome (241011323110142).

The spelling of 131010310100011 in words is "one hundred thirty-one trillion, ten billion, three hundred ten million, one hundred thousand, eleven".