13101032101130 has 16 divisors (see below), whose sum is σ = 23713600007520. Its totient is φ = 5211136790352.

The previous prime is 13101032101127. The next prime is 13101032101139. The reversal of 13101032101130 is 3110123010131.

13101032101130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×13101032101130² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13101032101099 and 13101032101108.

It is not an unprimeable number, because it can be changed into a prime (13101032101139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3659504384 + ... + 3659507963.

It is an arithmetic number, because the mean of its divisors is an integer number (1482100000470).

Almost surely, 2^{13101032101130} is an apocalyptic number.

13101032101130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13101032101130 is a deficient number, since it is larger than the sum of its proper divisors (10612567906390).

13101032101130 is a wasteful number, since it uses less digits than its factorization.

13101032101130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7319012533.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13101032101130 its reverse (3110123010131), we get a palindrome (16211155111261).

Subtracting from 13101032101130 its reverse (3110123010131), we obtain a palindrome (9990909090999).

The spelling of 13101032101130 in words is "thirteen trillion, one hundred one billion, thirty-two million, one hundred one thousand, one hundred thirty".