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13101034340431 is a prime number
BaseRepresentation
bin1011111010100101001001…
…1111111000000001001111
31201101110001121102210212001
42332221102133320001033
53204121404242343211
643510310533053131
72521342562334562
oct276512237700117
951343047383761
1013101034340431
1141a11323840a4
121577099a871a7
137405648697cb
143341445b24d9
1517abc45d7ac1
hexbea527f804f

13101034340431 has 2 divisors, whose sum is σ = 13101034340432. Its totient is φ = 13101034340430.

The previous prime is 13101034340351. The next prime is 13101034340461. The reversal of 13101034340431 is 13404343010131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13101034340431 - 217 = 13101034209359 is a prime.

It is a super-2 number, since 2×131010343404312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13101034340431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101034340461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550517170215 + 6550517170216.

It is an arithmetic number, because the mean of its divisors is an integer number (6550517170216).

Almost surely, 213101034340431 is an apocalyptic number.

13101034340431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101034340431 is an equidigital number, since it uses as much as digits as its factorization.

13101034340431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13101034340431 its reverse (13404343010131), we get a palindrome (26505377350562).

The spelling of 13101034340431 in words is "thirteen trillion, one hundred one billion, thirty-four million, three hundred forty thousand, four hundred thirty-one".