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131010413430397 is a prime number
BaseRepresentation
bin11101110010011100111101…
…001001111000011001111101
3122011212110202222010210021011
4131302130331021320121331
5114132433311314233042
61142345204132235221
736411122114152054
oct3562347511703175
9564773688123234
10131010413430397
1138820227a46546
121283a84246bb11
1358142c90a2857
14244cd1b62739b
151022d35135a17
hex77273d27867d

131010413430397 has 2 divisors, whose sum is σ = 131010413430398. Its totient is φ = 131010413430396.

The previous prime is 131010413430371. The next prime is 131010413430419. The reversal of 131010413430397 is 793034314010131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121499783017636 + 9510630412761 = 11022694^2 + 3083931^2 .

It is a cyclic number.

It is not a de Polignac number, because 131010413430397 - 243 = 122214320408189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131010413430307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505206715198 + 65505206715199.

It is an arithmetic number, because the mean of its divisors is an integer number (65505206715199).

Almost surely, 2131010413430397 is an apocalyptic number.

It is an amenable number.

131010413430397 is a deficient number, since it is larger than the sum of its proper divisors (1).

131010413430397 is an equidigital number, since it uses as much as digits as its factorization.

131010413430397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 40.

The spelling of 131010413430397 in words is "one hundred thirty-one trillion, ten billion, four hundred thirteen million, four hundred thirty thousand, three hundred ninety-seven".