Base | Representation |
---|---|
bin | 11101110010011100111101… |
… | …001100111110000100000111 |
3 | 122011212110210000122220211201 |
4 | 131302130331030332010013 |
5 | 114132433312021140012 |
6 | 1142345204201443331 |
7 | 36411122124063331 |
oct | 3562347514760407 |
9 | 564773700586751 |
10 | 131010414240007 |
11 | 38820228449845 |
12 | 1283a8427a0547 |
13 | 58142c92c7203 |
14 | 244cd1b798451 |
15 | 1022d35245857 |
hex | 77273d33e107 |
131010414240007 has 2 divisors, whose sum is σ = 131010414240008. Its totient is φ = 131010414240006.
The previous prime is 131010414239963. The next prime is 131010414240037. The reversal of 131010414240007 is 700042414010131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131010414240007 - 219 = 131010413715719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131010414240037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505207120003 + 65505207120004.
It is an arithmetic number, because the mean of its divisors is an integer number (65505207120004).
Almost surely, 2131010414240007 is an apocalyptic number.
131010414240007 is a deficient number, since it is larger than the sum of its proper divisors (1).
131010414240007 is an equidigital number, since it uses as much as digits as its factorization.
131010414240007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 131010414240007 its reverse (700042414010131), we get a palindrome (831052828250138).
The spelling of 131010414240007 in words is "one hundred thirty-one trillion, ten billion, four hundred fourteen million, two hundred forty thousand, seven".
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