Base | Representation |
---|---|
bin | 11000011001110001… |
… | …00000111001110000 |
3 | 1020211000220221211101 |
4 | 30030320200321300 |
5 | 203312331341222 |
6 | 10004000454144 |
7 | 642441013360 |
oct | 141470407160 |
9 | 36730827741 |
10 | 13101043312 |
11 | 5613219825 |
12 | 265761a354 |
13 | 130a2bc346 |
14 | 8c3d4c9a0 |
15 | 51a260927 |
hex | 30ce20e70 |
13101043312 has 40 divisors (see below), whose sum is σ = 29020539392. Its totient is φ = 5612587200.
The previous prime is 13101043309. The next prime is 13101043313. The reversal of 13101043312 is 21334010131.
It is a self number, because there is not a number n which added to its sum of digits gives 13101043312.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13101043313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 291637 + ... + 333547.
Almost surely, 213101043312 is an apocalyptic number.
It is an amenable number.
13101043312 is an abundant number, since it is smaller than the sum of its proper divisors (15919496080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101043312 is a wasteful number, since it uses less digits than its factorization.
13101043312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44717 (or 44711 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13101043312 its reverse (21334010131), we get a palindrome (34435053443).
The spelling of 13101043312 in words is "thirteen billion, one hundred one million, forty-three thousand, three hundred twelve".
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