131010440433111 has 48 divisors (see below), whose sum is σ = 195116348883456. Its totient is φ = 84658312061568.

The previous prime is 131010440433091. The next prime is 131010440433127. The reversal of 131010440433111 is 111334044010131.

131010440433111 is a `hidden beast` number, since 1 + 3 + 10 + 104 + 4 + 0 + 433 + 111 = 666.

It is not a de Polignac number, because 131010440433111 - 2⁷ = 131010440432983 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131010440431111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 159867736 + ... + 160685138.

It is an arithmetic number, because the mean of its divisors is an integer number (4064923935072).

Almost surely, 2^{131010440433111} is an apocalyptic number.

131010440433111 is a deficient number, since it is larger than the sum of its proper divisors (64105908450345).

131010440433111 is a wasteful number, since it uses less digits than its factorization.

131010440433111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 820612 (or 820609 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 131010440433111 its reverse (111334044010131), we get a palindrome (242344484443242).

The spelling of 131010440433111 in words is "one hundred thirty-one trillion, ten billion, four hundred forty million, four hundred thirty-three thousand, one hundred eleven".