Base | Representation |
---|---|
bin | 1011111010100101011100… |
… | …1001010001010111100111 |
3 | 1201101110021001010121200200 |
4 | 2332221113021101113213 |
5 | 3204122034222113111 |
6 | 43510322400041543 |
7 | 2521344530105136 |
oct | 276512711212747 |
9 | 51343231117620 |
10 | 13101112301031 |
11 | 41a1172392047 |
12 | 15771000032b3 |
13 | 740577a64841 |
14 | 334150aa791d |
15 | 17abcb387256 |
hex | bea572515e7 |
13101112301031 has 24 divisors (see below), whose sum is σ = 19635517958160. Its totient is φ = 8407422777600.
The previous prime is 13101112301029. The next prime is 13101112301033. The reversal of 13101112301031 is 13010321110131.
13101112301031 is a `hidden beast` number, since 1 + 310 + 11 + 12 + 301 + 0 + 31 = 666.
It is an interprime number because it is at equal distance from previous prime (13101112301029) and next prime (13101112301033).
It is not a de Polignac number, because 13101112301031 - 21 = 13101112301029 is a prime.
It is a super-2 number, since 2×131011123010312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13101112300995 and 13101112301013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13101112301033) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 75738130 + ... + 75910911.
It is an arithmetic number, because the mean of its divisors is an integer number (818146581590).
Almost surely, 213101112301031 is an apocalyptic number.
13101112301031 is a deficient number, since it is larger than the sum of its proper divisors (6534405657129).
13101112301031 is a wasteful number, since it uses less digits than its factorization.
13101112301031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151649407 (or 151649404 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 13101112301031 its reverse (13010321110131), we get a palindrome (26111433411162).
The spelling of 13101112301031 in words is "thirteen trillion, one hundred one billion, one hundred twelve million, three hundred one thousand, thirty-one".
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