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131011124214302 = 265505562107151
BaseRepresentation
bin11101110010011101100111…
…100001010011101000011110
3122011212112121111121100110222
4131302131213201103220132
5114132441240244324202
61142345402443001342
736411145534546253
oct3562354741235036
9564775544540428
10131011124214302
1138820562190a62
121283aa00509252
1358143b0419547
14244cd87bab42a
151022d777384a2
hex772767853a1e

131011124214302 has 4 divisors (see below), whose sum is σ = 196516686321456. Its totient is φ = 65505562107150.

The previous prime is 131011124214287. The next prime is 131011124214317. The reversal of 131011124214302 is 203412421110131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (131011124214287) and next prime (131011124214317).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32752781053574 + ... + 32752781053577.

It is an arithmetic number, because the mean of its divisors is an integer number (49129171580364).

Almost surely, 2131011124214302 is an apocalyptic number.

131011124214302 is a deficient number, since it is larger than the sum of its proper divisors (65505562107154).

131011124214302 is an equidigital number, since it uses as much as digits as its factorization.

131011124214302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65505562107153.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 131011124214302 its reverse (203412421110131), we get a palindrome (334423545324433).

The spelling of 131011124214302 in words is "one hundred thirty-one trillion, eleven billion, one hundred twenty-four million, two hundred fourteen thousand, three hundred two".

Divisors: 1 2 65505562107151 131011124214302