Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …110111011011001000010011 |
3 | 122011212112121220111220200011 |
4 | 131302131213313123020103 |
5 | 114132441243240342204 |
6 | 1142345403211135351 |
7 | 36411145635044554 |
oct | 3562354767331023 |
9 | 564775556456604 |
10 | 131011130012179 |
11 | 38820565490a9a |
12 | 1283aa02444557 |
13 | 58143b1699541 |
14 | 244cd8887a32b |
15 | 1022d77ed1304 |
hex | 772767ddb213 |
131011130012179 has 2 divisors, whose sum is σ = 131011130012180. Its totient is φ = 131011130012178.
The previous prime is 131011130012137. The next prime is 131011130012221. The reversal of 131011130012179 is 971210031110131.
It is a balanced prime because it is at equal distance from previous prime (131011130012137) and next prime (131011130012221).
It is a cyclic number.
It is not a de Polignac number, because 131011130012179 - 231 = 131008982528531 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131011130012179.
It is not a weakly prime, because it can be changed into another prime (131011130019179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505565006089 + 65505565006090.
It is an arithmetic number, because the mean of its divisors is an integer number (65505565006090).
Almost surely, 2131011130012179 is an apocalyptic number.
131011130012179 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011130012179 is an equidigital number, since it uses as much as digits as its factorization.
131011130012179 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 31.
The spelling of 131011130012179 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty million, twelve thousand, one hundred seventy-nine".
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