131011130012803 has 2 divisors, whose sum is σ = 131011130012804. Its totient is φ = 131011130012802.

The previous prime is 131011130012771. The next prime is 131011130012857. The reversal of 131011130012803 is 308210031110131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131011130012803 - 2⁵ = 131011130012771 is a prime.

It is not a weakly prime, because it can be changed into another prime (131011130042803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505565006401 + 65505565006402.

It is an arithmetic number, because the mean of its divisors is an integer number (65505565006402).

Almost surely, 2^{131011130012803} is an apocalyptic number.

131011130012803 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011130012803 is an equidigital number, since it uses as much as digits as its factorization.

131011130012803 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 131011130012803 its reverse (308210031110131), we get a palindrome (439221161122934).

The spelling of 131011130012803 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty million, twelve thousand, eight hundred three".