131011141020131 has 2 divisors, whose sum is σ = 131011141020132. Its totient is φ = 131011141020130.

The previous prime is 131011141020101. The next prime is 131011141020187. The reversal of 131011141020131 is 131020141110131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131011141020131 - 2¹⁴ = 131011141003747 is a prime.

It is a super-2 number, since 2×131011141020131² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131011141020101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505570510065 + 65505570510066.

It is an arithmetic number, because the mean of its divisors is an integer number (65505570510066).

Almost surely, 2^{131011141020131} is an apocalyptic number.

131011141020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011141020131 is an equidigital number, since it uses as much as digits as its factorization.

131011141020131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 131011141020131 its reverse (131020141110131), we get a palindrome (262031282130262).

The spelling of 131011141020131 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-one million, twenty thousand, one hundred thirty-one".