Base | Representation |
---|---|
bin | 11101110010011101101000… |
… | …100001011010101000011011 |
3 | 122011212112122200020011211011 |
4 | 131302131220201122220123 |
5 | 114132441304100121222 |
6 | 1142345404243114351 |
7 | 36411146130443101 |
oct | 3562355041325033 |
9 | 564775580204734 |
10 | 131011141020187 |
11 | 3882057071a51a |
12 | 1283aa060729b7 |
13 | 58143b3a51b5c |
14 | 244cd8a103c71 |
15 | 1022d78e57c77 |
hex | 77276885aa1b |
131011141020187 has 2 divisors, whose sum is σ = 131011141020188. Its totient is φ = 131011141020186.
The previous prime is 131011141020131. The next prime is 131011141020197. The reversal of 131011141020187 is 781020141110131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131011141020187 - 27 = 131011141020059 is a prime.
It is a super-2 number, since 2×1310111410201872 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131011141020197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505570510093 + 65505570510094.
It is an arithmetic number, because the mean of its divisors is an integer number (65505570510094).
Almost surely, 2131011141020187 is an apocalyptic number.
131011141020187 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011141020187 is an equidigital number, since it uses as much as digits as its factorization.
131011141020187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 31.
The spelling of 131011141020187 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-one million, twenty thousand, one hundred eighty-seven".
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