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131011202430257 is a prime number
BaseRepresentation
bin11101110010011101101100…
…001011101011010100110001
3122011212112210221210010121012
4131302131230023223110301
5114132441420310232012
61142345414315240305
736411150504432152
oct3562355413532461
9564775727703535
10131011202430257
11388205a2353846
121283aa22749095
1358143c36a3886
14244cd9432b929
151022d7e538622
hex77276c2eb531

131011202430257 has 2 divisors, whose sum is σ = 131011202430258. Its totient is φ = 131011202430256.

The previous prime is 131011202430179. The next prime is 131011202430337. The reversal of 131011202430257 is 752034202110131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127504837574416 + 3506364855841 = 11291804^2 + 1872529^2 .

It is an emirp because it is prime and its reverse (752034202110131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131011202430257 is a prime.

It is not a weakly prime, because it can be changed into another prime (131011208430257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505601215128 + 65505601215129.

It is an arithmetic number, because the mean of its divisors is an integer number (65505601215129).

Almost surely, 2131011202430257 is an apocalyptic number.

It is an amenable number.

131011202430257 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011202430257 is an equidigital number, since it uses as much as digits as its factorization.

131011202430257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 32.

Adding to 131011202430257 its reverse (752034202110131), we get a palindrome (883045404540388).

The spelling of 131011202430257 in words is "one hundred thirty-one trillion, eleven billion, two hundred two million, four hundred thirty thousand, two hundred fifty-seven".