Base | Representation |
---|---|
bin | 11101110010011101101100… |
… | …010001110010001000110011 |
3 | 122011212112211001210110102222 |
4 | 131302131230101302020303 |
5 | 114132441421212443102 |
6 | 1142345414413431255 |
7 | 36411150524150135 |
oct | 3562355421621063 |
9 | 564775731713388 |
10 | 131011204031027 |
11 | 388205a32474a1 |
12 | 1283aa2319b52b |
13 | 58143c3b14388 |
14 | 244cd94627055 |
15 | 1022d7e752aa2 |
hex | 77276c472233 |
131011204031027 has 2 divisors, whose sum is σ = 131011204031028. Its totient is φ = 131011204031026.
The previous prime is 131011204031021. The next prime is 131011204031063. The reversal of 131011204031027 is 720130402110131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131011204031027 - 212 = 131011204026931 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131011204030987 and 131011204031005.
It is not a weakly prime, because it can be changed into another prime (131011204031021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505602015513 + 65505602015514.
It is an arithmetic number, because the mean of its divisors is an integer number (65505602015514).
Almost surely, 2131011204031027 is an apocalyptic number.
131011204031027 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011204031027 is an equidigital number, since it uses as much as digits as its factorization.
131011204031027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 131011204031027 its reverse (720130402110131), we get a palindrome (851141606141158).
The spelling of 131011204031027 in words is "one hundred thirty-one trillion, eleven billion, two hundred four million, thirty-one thousand, twenty-seven".
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