Base | Representation |
---|---|
bin | 11101110010011101101100… |
… | …010001110010001001010111 |
3 | 122011212112211001210110111022 |
4 | 131302131230101302021113 |
5 | 114132441421212443223 |
6 | 1142345414413431355 |
7 | 36411150524150216 |
oct | 3562355421621127 |
9 | 564775731713438 |
10 | 131011204031063 |
11 | 388205a3247524 |
12 | 1283aa2319b55b |
13 | 58143c3b143b5 |
14 | 244cd9462707d |
15 | 1022d7e752ac8 |
hex | 77276c472257 |
131011204031063 has 2 divisors, whose sum is σ = 131011204031064. Its totient is φ = 131011204031062.
The previous prime is 131011204031027. The next prime is 131011204031089. The reversal of 131011204031063 is 360130402110131.
It is an a-pointer prime, because the next prime (131011204031089) can be obtained adding 131011204031063 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131011204031063 - 26 = 131011204030999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131011204001063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505602015531 + 65505602015532.
It is an arithmetic number, because the mean of its divisors is an integer number (65505602015532).
Almost surely, 2131011204031063 is an apocalyptic number.
131011204031063 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011204031063 is an equidigital number, since it uses as much as digits as its factorization.
131011204031063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 131011204031063 its reverse (360130402110131), we get a palindrome (491141606141194).
The spelling of 131011204031063 in words is "one hundred thirty-one trillion, eleven billion, two hundred four million, thirty-one thousand, sixty-three".
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