Base | Representation |
---|---|
bin | 1011111010100101011110… |
… | …1010100010100001001111 |
3 | 1201101110021122112200122200 |
4 | 2332221113222202201033 |
5 | 3204122043440201111 |
6 | 43510323311012543 |
7 | 2521344664166610 |
oct | 276512752424117 |
9 | 51343248480580 |
10 | 13101121022031 |
11 | 41a11772a9289 |
12 | 1577102b0a153 |
13 | 7405797c91b3 |
14 | 334151cd7c07 |
15 | 17abcc00b256 |
hex | bea57aa284f |
13101121022031 has 24 divisors (see below), whose sum is σ = 21981792447264. Its totient is φ = 7363627738560.
The previous prime is 13101121022029. The next prime is 13101121022069. The reversal of 13101121022031 is 13022012110131.
It is not a de Polignac number, because 13101121022031 - 21 = 13101121022029 is a prime.
It is a super-2 number, since 2×131011210220312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13101121021995 and 13101121022013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13101121022071) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1704539616 + ... + 1704547301.
It is an arithmetic number, because the mean of its divisors is an integer number (915908018636).
Almost surely, 213101121022031 is an apocalyptic number.
13101121022031 is a deficient number, since it is larger than the sum of its proper divisors (8880671425233).
13101121022031 is a wasteful number, since it uses less digits than its factorization.
13101121022031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3409086991 (or 3409086988 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 13101121022031 its reverse (13022012110131), we get a palindrome (26123133132162).
The spelling of 13101121022031 in words is "thirteen trillion, one hundred one billion, one hundred twenty-one million, twenty-two thousand, thirty-one".
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