Base | Representation |
---|---|
bin | 1011111010100101011110… |
… | …1010100100110000110101 |
3 | 1201101110021122120011021001 |
4 | 2332221113222210300311 |
5 | 3204122043440444341 |
6 | 43510323311123301 |
7 | 2521344664235446 |
oct | 276512752446065 |
9 | 51343248504231 |
10 | 13101121031221 |
11 | 41a1177305183 |
12 | 1577102b13531 |
13 | 740579800432 |
14 | 334151cdb2cd |
15 | 17abcc00dd31 |
hex | bea57aa4c35 |
13101121031221 has 2 divisors, whose sum is σ = 13101121031222. Its totient is φ = 13101121031220.
The previous prime is 13101121031197. The next prime is 13101121031233. The reversal of 13101121031221 is 12213012110131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12668716150596 + 432404880625 = 3559314^2 + 657575^2 .
It is a cyclic number.
It is not a de Polignac number, because 13101121031221 - 211 = 13101121029173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13101121031281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550560515610 + 6550560515611.
It is an arithmetic number, because the mean of its divisors is an integer number (6550560515611).
Almost surely, 213101121031221 is an apocalyptic number.
It is an amenable number.
13101121031221 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101121031221 is an equidigital number, since it uses as much as digits as its factorization.
13101121031221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 13101121031221 its reverse (12213012110131), we get a palindrome (25314133141352).
The spelling of 13101121031221 in words is "thirteen trillion, one hundred one billion, one hundred twenty-one million, thirty-one thousand, two hundred twenty-one".
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