Base | Representation |
---|---|
bin | 111101000000011100… |
… | …0011101001010001111 |
3 | 110112011101212201012121 |
4 | 1322000320131022033 |
5 | 4121302343131111 |
6 | 140104042513411 |
7 | 12315403456531 |
oct | 1720070351217 |
9 | 415141781177 |
10 | 131011302031 |
11 | 5061a512335 |
12 | 21483505867 |
13 | c47b56b0bc |
14 | 64ab919851 |
15 | 361ba28871 |
hex | 1e80e1d28f |
131011302031 has 2 divisors, whose sum is σ = 131011302032. Its totient is φ = 131011302030.
The previous prime is 131011302011. The next prime is 131011302139. The reversal of 131011302031 is 130203110131.
It is a weak prime.
It is an emirp because it is prime and its reverse (130203110131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131011302031 - 211 = 131011299983 is a prime.
It is a super-2 number, since 2×1310113020312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131011301996 and 131011302014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131011302011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505651015 + 65505651016.
It is an arithmetic number, because the mean of its divisors is an integer number (65505651016).
Almost surely, 2131011302031 is an apocalyptic number.
131011302031 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011302031 is an equidigital number, since it uses as much as digits as its factorization.
131011302031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131011302031 its reverse (130203110131), we get a palindrome (261214412162).
The spelling of 131011302031 in words is "one hundred thirty-one billion, eleven million, three hundred two thousand, thirty-one".
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