Base | Representation |
---|---|
bin | 111101000000011100… |
… | …0100100100011010011 |
3 | 110112011101221020201221 |
4 | 1322000320210203103 |
5 | 4121302400113212 |
6 | 140104043305511 |
7 | 12315403644022 |
oct | 1720070444323 |
9 | 415141836657 |
10 | 131011332307 |
11 | 5061a533059 |
12 | 2148351b297 |
13 | c47b57bb0b |
14 | 64ab9268b9 |
15 | 361ba32807 |
hex | 1e80e248d3 |
131011332307 has 2 divisors, whose sum is σ = 131011332308. Its totient is φ = 131011332306.
The previous prime is 131011332259. The next prime is 131011332373. The reversal of 131011332307 is 703233110131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131011332307 - 215 = 131011299539 is a prime.
It is not a weakly prime, because it can be changed into another prime (131011732307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505666153 + 65505666154.
It is an arithmetic number, because the mean of its divisors is an integer number (65505666154).
Almost surely, 2131011332307 is an apocalyptic number.
131011332307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011332307 is an equidigital number, since it uses as much as digits as its factorization.
131011332307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 131011332307 its reverse (703233110131), we get a palindrome (834244442438).
The spelling of 131011332307 in words is "one hundred thirty-one billion, eleven million, three hundred thirty-two thousand, three hundred seven".
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