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131011409999957 is a prime number
BaseRepresentation
bin11101110010011101111000…
…100011011111100001010101
3122011212120100102100202200212
4131302131320203133201111
5114132442331424444312
61142345451052215205
736411155604644504
oct3562357043374125
9564776312322625
10131011409999957
1138820699536a53
121283aa8016a505
1358144276ab496
14244cdb3b2083b
151022d9288a822
hex7727788df855

131011409999957 has 2 divisors, whose sum is σ = 131011409999958. Its totient is φ = 131011409999956.

The previous prime is 131011409999927. The next prime is 131011409999969. The reversal of 131011409999957 is 759999904110131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129731052122116 + 1280357877841 = 11389954^2 + 1131529^2 .

It is a cyclic number.

It is not a de Polignac number, because 131011409999957 - 26 = 131011409999893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131011409999927) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505704999978 + 65505704999979.

It is an arithmetic number, because the mean of its divisors is an integer number (65505704999979).

Almost surely, 2131011409999957 is an apocalyptic number.

It is an amenable number.

131011409999957 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011409999957 is an equidigital number, since it uses as much as digits as its factorization.

131011409999957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24800580, while the sum is 68.

The spelling of 131011409999957 in words is "one hundred thirty-one trillion, eleven billion, four hundred nine million, nine hundred ninety-nine thousand, nine hundred fifty-seven".