Base | Representation |
---|---|
bin | 11101110010011101111001… |
… | …110100010111110100110111 |
3 | 122011212120101220020221120112 |
4 | 131302131321310113310313 |
5 | 114132442402341431403 |
6 | 1142345453130453235 |
7 | 36411156253111364 |
oct | 3562357164276467 |
9 | 564776356227515 |
10 | 131011431202103 |
11 | 388206aa4a8491 |
12 | 1283aa8729421b |
13 | 581442bbc2b2a |
14 | 244cdb687d46b |
15 | 1022d946779d8 |
hex | 772779d17d37 |
131011431202103 has 2 divisors, whose sum is σ = 131011431202104. Its totient is φ = 131011431202102.
The previous prime is 131011431202073. The next prime is 131011431202111. The reversal of 131011431202103 is 301202134110131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131011431202103 - 218 = 131011430939959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131011431202133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505715601051 + 65505715601052.
It is an arithmetic number, because the mean of its divisors is an integer number (65505715601052).
Almost surely, 2131011431202103 is an apocalyptic number.
131011431202103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011431202103 is an equidigital number, since it uses as much as digits as its factorization.
131011431202103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 131011431202103 its reverse (301202134110131), we get a palindrome (432213565312234).
The spelling of 131011431202103 in words is "one hundred thirty-one trillion, eleven billion, four hundred thirty-one million, two hundred two thousand, one hundred three".
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