Base | Representation |
---|---|
bin | 1011111010100101110001… |
… | …1111100010001011101000 |
3 | 1201101110111021221222021220 |
4 | 2332221130133202023220 |
5 | 3204122230204220034 |
6 | 43510335323102040 |
7 | 2521346666532504 |
oct | 276513437421350 |
9 | 51343437858256 |
10 | 13101202023144 |
11 | 41a1208aa3654 |
12 | 1577126071920 |
13 | 74059051a151 |
14 | 33415c981304 |
15 | 17abd41ab749 |
hex | bea5c7e22e8 |
13101202023144 has 32 divisors (see below), whose sum is σ = 32753099826720. Its totient is φ = 4367054705216.
The previous prime is 13101202023113. The next prime is 13101202023241. The reversal of 13101202023144 is 44132020210131.
It is a super-3 number, since 3×131012020231443 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11724934 + ... + 12793610.
It is an arithmetic number, because the mean of its divisors is an integer number (1023534369585).
Almost surely, 213101202023144 is an apocalyptic number.
It is an amenable number.
13101202023144 is an abundant number, since it is smaller than the sum of its proper divisors (19651897803576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101202023144 is a wasteful number, since it uses less digits than its factorization.
13101202023144 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1579489 (or 1579485 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13101202023144 its reverse (44132020210131), we get a palindrome (57233222233275).
The spelling of 13101202023144 in words is "thirteen trillion, one hundred one billion, two hundred two million, twenty-three thousand, one hundred forty-four".
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