Search a number
-
+
1310120311310 = 25131012031131
BaseRepresentation
bin10011000100001001010…
…000010111101000001110
311122020122112111112102222
4103010021100113220032
5132431111244430220
62441505545015342
7163440000622226
oct23041120275016
94566575445388
101310120311310
11465689840938
12191ab0784552
139670b9ba425
14475a56a9086
152412c64ae25
hex13109417a0e

1310120311310 has 8 divisors (see below), whose sum is σ = 2358216560376. Its totient is φ = 524048124520.

The previous prime is 1310120311289. The next prime is 1310120311351. The reversal of 1310120311310 is 131130210131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13101203113102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65506015556 + ... + 65506015575.

It is an arithmetic number, because the mean of its divisors is an integer number (294777070047).

Almost surely, 21310120311310 is an apocalyptic number.

1310120311310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310120311310 is a deficient number, since it is larger than the sum of its proper divisors (1048096249066).

1310120311310 is a wasteful number, since it uses less digits than its factorization.

1310120311310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131012031138.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1310120311310 its reverse (131130210131), we get a palindrome (1441250521441).

The spelling of 1310120311310 in words is "one trillion, three hundred ten billion, one hundred twenty million, three hundred eleven thousand, three hundred ten".

Divisors: 1 2 5 10 131012031131 262024062262 655060155655 1310120311310