Base | Representation |
---|---|
bin | 11101110010011110100011… |
… | …101001111111000001010100 |
3 | 122011212122012211001011211122 |
4 | 131302132203221333001110 |
5 | 114133000322034402012 |
6 | 1142350050523223112 |
7 | 36411212535250433 |
oct | 3562364351770124 |
9 | 564778184034748 |
10 | 131012133122132 |
11 | 38820a2a739389 |
12 | 1283b042377a98 |
13 | 5814511455122 |
14 | 244d041b9711a |
15 | 1022dd60c8e72 |
hex | 7727a3a7f054 |
131012133122132 has 24 divisors (see below), whose sum is σ = 230088979184064. Its totient is φ = 65272819119552.
The previous prime is 131012133122131. The next prime is 131012133122201. The reversal of 131012133122132 is 231221331210131.
It is a super-2 number, since 2×1310121331221322 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131012133122131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47962418 + ... + 50620329.
It is an arithmetic number, because the mean of its divisors is an integer number (9587040799336).
Almost surely, 2131012133122132 is an apocalyptic number.
It is an amenable number.
131012133122132 is a deficient number, since it is larger than the sum of its proper divisors (99076846061932).
131012133122132 is a wasteful number, since it uses less digits than its factorization.
131012133122132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98583935 (or 98583933 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 131012133122132 its reverse (231221331210131), we get a palindrome (362233464332263).
The spelling of 131012133122132 in words is "one hundred thirty-one trillion, twelve billion, one hundred thirty-three million, one hundred twenty-two thousand, one hundred thirty-two".
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