13101214111 has 4 divisors (see below), whose sum is σ = 13236278272. Its totient is φ = 12966149952.

The previous prime is 13101214109. The next prime is 13101214127. The reversal of 13101214111 is 11141210131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11141210131 = 673 ⋅16554547.

It is a cyclic number.

It is not a de Polignac number, because 13101214111 - 2¹ = 13101214109 is a prime.

It is a super-3 number, since 3×13101214111³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13161214111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67531935 + ... + 67532128.

It is an arithmetic number, because the mean of its divisors is an integer number (3309069568).

Almost surely, 2^13101214111 is an apocalyptic number.

13101214111 is a deficient number, since it is larger than the sum of its proper divisors (135064161).

13101214111 is an equidigital number, since it uses as much as digits as its factorization.

13101214111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135064160.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 13101214111 its reverse (11141210131), we get a palindrome (24242424242).

The spelling of 13101214111 in words is "thirteen billion, one hundred one million, two hundred fourteen thousand, one hundred eleven".