131012143404001 has 2 divisors, whose sum is σ = 131012143404002. Its totient is φ = 131012143404000.

The previous prime is 131012143403971. The next prime is 131012143404019. The reversal of 131012143404001 is 100404341210131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71128999307601 + 59883144096400 = 8433801^2 + 7738420^2 .

It is a cyclic number.

It is not a de Polignac number, because 131012143404001 - 2⁷ = 131012143403873 is a prime.

It is not a weakly prime, because it can be changed into another prime (131012143404041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506071702000 + 65506071702001.

It is an arithmetic number, because the mean of its divisors is an integer number (65506071702001).

Almost surely, 2^{131012143404001} is an apocalyptic number.

It is an amenable number.

131012143404001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012143404001 is an equidigital number, since it uses as much as digits as its factorization.

131012143404001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131012143404001 its reverse (100404341210131), we get a palindrome (231416484614132).

The spelling of 131012143404001 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-three million, four hundred four thousand, one".