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131012144092391 is a prime number
BaseRepresentation
bin11101110010011110100100…
…010011110101010011100111
3122011212122020120200112012112
4131302132210103311103213
5114133000332341424031
61142350051554311235
736411213030430622
oct3562364423652347
9564778216615175
10131012144092391
1138820a35951511
121283b045b8851b
1358145137c64c3
14244d043410db9
151022dd704462b
hex7727a44f54e7

131012144092391 has 2 divisors, whose sum is σ = 131012144092392. Its totient is φ = 131012144092390.

The previous prime is 131012144092381. The next prime is 131012144092411. The reversal of 131012144092391 is 193290441210131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131012144092391 - 218 = 131012143830247 is a prime.

It is a super-2 number, since 2×1310121440923912 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131012144092381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506072046195 + 65506072046196.

It is an arithmetic number, because the mean of its divisors is an integer number (65506072046196).

Almost surely, 2131012144092391 is an apocalyptic number.

131012144092391 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012144092391 is an equidigital number, since it uses as much as digits as its factorization.

131012144092391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46656, while the sum is 41.

The spelling of 131012144092391 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-four million, ninety-two thousand, three hundred ninety-one".