Base | Representation |
---|---|
bin | 11101110010011110100100… |
… | …010011110101010011100111 |
3 | 122011212122020120200112012112 |
4 | 131302132210103311103213 |
5 | 114133000332341424031 |
6 | 1142350051554311235 |
7 | 36411213030430622 |
oct | 3562364423652347 |
9 | 564778216615175 |
10 | 131012144092391 |
11 | 38820a35951511 |
12 | 1283b045b8851b |
13 | 58145137c64c3 |
14 | 244d043410db9 |
15 | 1022dd704462b |
hex | 7727a44f54e7 |
131012144092391 has 2 divisors, whose sum is σ = 131012144092392. Its totient is φ = 131012144092390.
The previous prime is 131012144092381. The next prime is 131012144092411. The reversal of 131012144092391 is 193290441210131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131012144092391 - 218 = 131012143830247 is a prime.
It is a super-2 number, since 2×1310121440923912 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131012144092381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506072046195 + 65506072046196.
It is an arithmetic number, because the mean of its divisors is an integer number (65506072046196).
Almost surely, 2131012144092391 is an apocalyptic number.
131012144092391 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012144092391 is an equidigital number, since it uses as much as digits as its factorization.
131012144092391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 41.
The spelling of 131012144092391 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-four million, ninety-two thousand, three hundred ninety-one".
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