Base | Representation |
---|---|
bin | 11101110010011110101000… |
… | …111001001101110111110011 |
3 | 122011212122102221101220021001 |
4 | 131302132220321031313303 |
5 | 114133001012034014303 |
6 | 1142350103342542431 |
7 | 36411214653230563 |
oct | 3562365071156763 |
9 | 564778387356231 |
10 | 131012221001203 |
11 | 38820a75301213 |
12 | 1283b067897a17 |
13 | 5814526713889 |
14 | 244d04d710da3 |
15 | 1022dddb8731d |
hex | 7727a8e4ddf3 |
131012221001203 has 2 divisors, whose sum is σ = 131012221001204. Its totient is φ = 131012221001202.
The previous prime is 131012221001197. The next prime is 131012221001209. The reversal of 131012221001203 is 302100122210131.
It is a balanced prime because it is at equal distance from previous prime (131012221001197) and next prime (131012221001209).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131012221001203 is a prime.
It is not a weakly prime, because it can be changed into another prime (131012221001209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506110500601 + 65506110500602.
It is an arithmetic number, because the mean of its divisors is an integer number (65506110500602).
Almost surely, 2131012221001203 is an apocalyptic number.
131012221001203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012221001203 is an equidigital number, since it uses as much as digits as its factorization.
131012221001203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 131012221001203 its reverse (302100122210131), we get a palindrome (433112343211334).
The spelling of 131012221001203 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-one million, one thousand, two hundred three".
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