Base | Representation |
---|---|
bin | 11101110010011110101000… |
… | …111010011010000101111001 |
3 | 122011212122102221222202111221 |
4 | 131302132220322122011321 |
5 | 114133001012124012101 |
6 | 1142350103353352041 |
7 | 36411214656001021 |
oct | 3562365072320571 |
9 | 564778387882457 |
10 | 131012221313401 |
11 | 38820a754a482a |
12 | 1283b067a08621 |
13 | 58145267c29cc |
14 | 244d04d792a81 |
15 | 1022dddbe9aa1 |
hex | 7727a8e9a179 |
131012221313401 has 2 divisors, whose sum is σ = 131012221313402. Its totient is φ = 131012221313400.
The previous prime is 131012221313377. The next prime is 131012221313417. The reversal of 131012221313401 is 104313122210131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74386295313001 + 56625926000400 = 8624749^2 + 7525020^2 .
It is a cyclic number.
It is not a de Polignac number, because 131012221313401 - 217 = 131012221182329 is a prime.
It is not a weakly prime, because it can be changed into another prime (131012221311401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506110656700 + 65506110656701.
It is an arithmetic number, because the mean of its divisors is an integer number (65506110656701).
Almost surely, 2131012221313401 is an apocalyptic number.
It is an amenable number.
131012221313401 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012221313401 is an equidigital number, since it uses as much as digits as its factorization.
131012221313401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 131012221313401 its reverse (104313122210131), we get a palindrome (235325343523532).
The spelling of 131012221313401 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-one million, three hundred thirteen thousand, four hundred one".
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