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131012221402177 is a prime number
BaseRepresentation
bin11101110010011110101000…
…111010101111110001000001
3122011212122102222011021021221
4131302132220322233301001
5114133001012134332202
61142350103355315041
736411214656520603
oct3562365072576101
9564778388137257
10131012221402177
1138820a755554a5
121283b067a4ba81
13581452682423b
14244d04d7b7173
151022dddc16037
hex7727a8eafc41

131012221402177 has 2 divisors, whose sum is σ = 131012221402178. Its totient is φ = 131012221402176.

The previous prime is 131012221402079. The next prime is 131012221402229. The reversal of 131012221402177 is 771204122210131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104642342906256 + 26369878495921 = 10229484^2 + 5135161^2 .

It is an emirp because it is prime and its reverse (771204122210131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131012221402177 - 215 = 131012221369409 is a prime.

It is not a weakly prime, because it can be changed into another prime (131012221403177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506110701088 + 65506110701089.

It is an arithmetic number, because the mean of its divisors is an integer number (65506110701089).

Almost surely, 2131012221402177 is an apocalyptic number.

It is an amenable number.

131012221402177 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012221402177 is an equidigital number, since it uses as much as digits as its factorization.

131012221402177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9408, while the sum is 34.

The spelling of 131012221402177 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-one million, four hundred two thousand, one hundred seventy-seven".