Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000100110011010011010111 |
3 | 122011212122110011010012002211 |
4 | 131302132221010303103113 |
5 | 114133001013323204403 |
6 | 1142350103532014251 |
7 | 36411215021106532 |
oct | 3562365104632327 |
9 | 564778404105084 |
10 | 131012224038103 |
11 | 38820a76a95951 |
12 | 1283b068901387 |
13 | 5814527237c65 |
14 | 244d04dca1a19 |
15 | 1022dde08706d |
hex | 7727a91334d7 |
131012224038103 has 2 divisors, whose sum is σ = 131012224038104. Its totient is φ = 131012224038102.
The previous prime is 131012224038077. The next prime is 131012224038139. The reversal of 131012224038103 is 301830422210131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131012224038103 - 217 = 131012223907031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131012224038173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112019051 + 65506112019052.
It is an arithmetic number, because the mean of its divisors is an integer number (65506112019052).
Almost surely, 2131012224038103 is an apocalyptic number.
131012224038103 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012224038103 is an equidigital number, since it uses as much as digits as its factorization.
131012224038103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 131012224038103 its reverse (301830422210131), we get a palindrome (432842646248234).
The spelling of 131012224038103 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, thirty-eight thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •