Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000100110011110010101011 |
3 | 122011212122110011010021212001 |
4 | 131302132221010303302223 |
5 | 114133001013323240412 |
6 | 1142350103532031431 |
7 | 36411215021115424 |
oct | 3562365104636253 |
9 | 564778404107761 |
10 | 131012224040107 |
11 | 38820a76a97403 |
12 | 1283b068902577 |
13 | 5814527238b47 |
14 | 244d04dca264b |
15 | 1022dde087957 |
hex | 7727a9133cab |
131012224040107 has 2 divisors, whose sum is σ = 131012224040108. Its totient is φ = 131012224040106.
The previous prime is 131012224040083. The next prime is 131012224040129. The reversal of 131012224040107 is 701040422210131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131012224040107 - 239 = 130462468226219 is a prime.
It is not a weakly prime, because it can be changed into another prime (131012224040167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112020053 + 65506112020054.
It is an arithmetic number, because the mean of its divisors is an integer number (65506112020054).
Almost surely, 2131012224040107 is an apocalyptic number.
131012224040107 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012224040107 is an equidigital number, since it uses as much as digits as its factorization.
131012224040107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 131012224040107 its reverse (701040422210131), we get a palindrome (832052646250238).
The spelling of 131012224040107 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, forty thousand, one hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •