Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000100110011110011000001 |
3 | 122011212122110011010021212212 |
4 | 131302132221010303303001 |
5 | 114133001013323241004 |
6 | 1142350103532031505 |
7 | 36411215021115455 |
oct | 3562365104636301 |
9 | 564778404107785 |
10 | 131012224040129 |
11 | 38820a76a97423 |
12 | 1283b068902595 |
13 | 5814527238b63 |
14 | 244d04dca2665 |
15 | 1022dde08796e |
hex | 7727a9133cc1 |
131012224040129 has 2 divisors, whose sum is σ = 131012224040130. Its totient is φ = 131012224040128.
The previous prime is 131012224040107. The next prime is 131012224040149. The reversal of 131012224040129 is 921040422210131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76306304681104 + 54705919359025 = 8735348^2 + 7396345^2 .
It is a cyclic number.
It is not a de Polignac number, because 131012224040129 - 212 = 131012224036033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131012224040095 and 131012224040104.
It is not a weakly prime, because it can be changed into another prime (131012224040149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112020064 + 65506112020065.
It is an arithmetic number, because the mean of its divisors is an integer number (65506112020065).
Almost surely, 2131012224040129 is an apocalyptic number.
It is an amenable number.
131012224040129 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012224040129 is an equidigital number, since it uses as much as digits as its factorization.
131012224040129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 32.
The spelling of 131012224040129 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, forty thousand, one hundred twenty-nine".
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