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131012224040219 = 293447140696383
BaseRepresentation
bin11101110010011110101001…
…000100110011110100011011
3122011212122110011010022000012
4131302132221010303310123
5114133001013323241334
61142350103532032135
736411215021115644
oct3562365104636433
9564778404108005
10131012224040219
1138820a76a974a5
121283b06890264b
135814527238c02
14244d04dca26cb
151022dde0879ce
hex7727a9133d1b

131012224040219 has 4 divisors (see below), whose sum is σ = 131459364736896. Its totient is φ = 130565083343544.

The previous prime is 131012224040197. The next prime is 131012224040251. The reversal of 131012224040219 is 912040422210131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131012224040219 is a prime.

It is a super-2 number, since 2×1310122240402192 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131012224040419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223570347899 + ... + 223570348484.

It is an arithmetic number, because the mean of its divisors is an integer number (32864841184224).

Almost surely, 2131012224040219 is an apocalyptic number.

131012224040219 is a deficient number, since it is larger than the sum of its proper divisors (447140696677).

131012224040219 is an equidigital number, since it uses as much as digits as its factorization.

131012224040219 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 447140696676.

The product of its (nonzero) digits is 6912, while the sum is 32.

The spelling of 131012224040219 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, forty thousand, two hundred nineteen".

Divisors: 1 293 447140696383 131012224040219