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131012224040197 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000100110011110100000101
3122011212122110011010021222101
4131302132221010303310011
5114133001013323241242
61142350103532032101
736411215021115613
oct3562365104636405
9564778404107871
10131012224040197
1138820a76a97485
121283b068902631
135814527238bb6
14244d04dca26b3
151022dde0879b7
hex7727a9133d05

131012224040197 has 2 divisors, whose sum is σ = 131012224040198. Its totient is φ = 131012224040196.

The previous prime is 131012224040177. The next prime is 131012224040251. The reversal of 131012224040197 is 791040422210131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129480753439521 + 1531470600676 = 11378961^2 + 1237526^2 .

It is an emirp because it is prime and its reverse (791040422210131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131012224040197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131012224040107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112020098 + 65506112020099.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112020099).

Almost surely, 2131012224040197 is an apocalyptic number.

It is an amenable number.

131012224040197 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224040197 is an equidigital number, since it uses as much as digits as its factorization.

131012224040197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 37.

The spelling of 131012224040197 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, forty thousand, one hundred ninety-seven".