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131012224040251 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000100110011110100111011
3122011212122110011010022001101
4131302132221010303310323
5114133001013323242001
61142350103532032231
736411215021116021
oct3562365104636473
9564778404108041
10131012224040251
1138820a76a97524
121283b068902677
135814527238c28
14244d04dca2711
151022dde087a01
hex7727a9133d3b

131012224040251 has 2 divisors, whose sum is σ = 131012224040252. Its totient is φ = 131012224040250.

The previous prime is 131012224040197. The next prime is 131012224040267. The reversal of 131012224040251 is 152040422210131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131012224040251 is a prime.

It is not a weakly prime, because it can be changed into another prime (131012224043251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112020125 + 65506112020126.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112020126).

Almost surely, 2131012224040251 is an apocalyptic number.

131012224040251 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224040251 is an equidigital number, since it uses as much as digits as its factorization.

131012224040251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 131012224040251 its reverse (152040422210131), we get a palindrome (283052646250382).

The spelling of 131012224040251 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, forty thousand, two hundred fifty-one".