Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000100110011110100111011 |
3 | 122011212122110011010022001101 |
4 | 131302132221010303310323 |
5 | 114133001013323242001 |
6 | 1142350103532032231 |
7 | 36411215021116021 |
oct | 3562365104636473 |
9 | 564778404108041 |
10 | 131012224040251 |
11 | 38820a76a97524 |
12 | 1283b068902677 |
13 | 5814527238c28 |
14 | 244d04dca2711 |
15 | 1022dde087a01 |
hex | 7727a9133d3b |
131012224040251 has 2 divisors, whose sum is σ = 131012224040252. Its totient is φ = 131012224040250.
The previous prime is 131012224040197. The next prime is 131012224040267. The reversal of 131012224040251 is 152040422210131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131012224040251 is a prime.
It is not a weakly prime, because it can be changed into another prime (131012224043251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112020125 + 65506112020126.
It is an arithmetic number, because the mean of its divisors is an integer number (65506112020126).
Almost surely, 2131012224040251 is an apocalyptic number.
131012224040251 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012224040251 is an equidigital number, since it uses as much as digits as its factorization.
131012224040251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 131012224040251 its reverse (152040422210131), we get a palindrome (283052646250382).
The spelling of 131012224040251 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, forty thousand, two hundred fifty-one".
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