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131012224134403 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000101001010110100000011
3122011212122110011022002012111
4131302132221011022310003
5114133001013334300103
61142350103534040151
736411215021660353
oct3562365105126403
9564778404262174
10131012224134403
1138820a77051237
121283b068949057
13581452726ca41
14244d04dcc8b63
151022dde0a586d
hex7727a914ad03

131012224134403 has 2 divisors, whose sum is σ = 131012224134404. Its totient is φ = 131012224134402.

The previous prime is 131012224134397. The next prime is 131012224134431. The reversal of 131012224134403 is 304431422210131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131012224134403 - 225 = 131012190579971 is a prime.

It is not a weakly prime, because it can be changed into another prime (131012224164403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112067201 + 65506112067202.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112067202).

Almost surely, 2131012224134403 is an apocalyptic number.

131012224134403 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224134403 is an equidigital number, since it uses as much as digits as its factorization.

131012224134403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 131012224134403 its reverse (304431422210131), we get a palindrome (435443646344534).

The spelling of 131012224134403 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, one hundred thirty-four thousand, four hundred three".