Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000101011011010100111001 |
3 | 122011212122110011102111222121 |
4 | 131302132221011123110321 |
5 | 114133001013343431131 |
6 | 1142350103535321241 |
7 | 36411215022361510 |
oct | 3562365105332471 |
9 | 564778404374877 |
10 | 131012224202041 |
11 | 38820a77098036 |
12 | 1283b068980221 |
13 | 5814527294770 |
14 | 244d04dd05677 |
15 | 1022dde0ba911 |
hex | 7727a915b539 |
131012224202041 has 32 divisors (see below), whose sum is σ = 166527054102528. Its totient is φ = 100266145600320.
The previous prime is 131012224202029. The next prime is 131012224202047. The reversal of 131012224202041 is 140202422210131.
It is not a de Polignac number, because 131012224202041 - 245 = 95827852113209 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131012224201997 and 131012224202015.
It is not an unprimeable number, because it can be changed into a prime (131012224202047) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5239015 + ... + 17013868.
It is an arithmetic number, because the mean of its divisors is an integer number (5203970440704).
Almost surely, 2131012224202041 is an apocalyptic number.
It is an amenable number.
131012224202041 is a deficient number, since it is larger than the sum of its proper divisors (35514829900487).
131012224202041 is a wasteful number, since it uses less digits than its factorization.
131012224202041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22255021.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 131012224202041 its reverse (140202422210131), we get a palindrome (271214646412172).
The spelling of 131012224202041 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred two thousand, forty-one".
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