131012224204117 has 2 divisors, whose sum is σ = 131012224204118. Its totient is φ = 131012224204116.

The previous prime is 131012224204093. The next prime is 131012224204151. The reversal of 131012224204117 is 711402422210131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130978159595761 + 34064608356 = 11444569^2 + 184566^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131012224204117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131012224204417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112102058 + 65506112102059.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112102059).

Almost surely, 2^{131012224204117} is an apocalyptic number.

It is an amenable number.

131012224204117 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224204117 is an equidigital number, since it uses as much as digits as its factorization.

131012224204117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 31.

Adding to 131012224204117 its reverse (711402422210131), we get a palindrome (842414646414248).

The spelling of 131012224204117 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred four thousand, one hundred seventeen".