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131012224204573 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000101011011111100011101
3122011212122110011102122110101
4131302132221011123330131
5114133001013344021243
61142350103535341101
736411215022402055
oct3562365105337435
9564778404378411
10131012224204573
1138820a77099a28
121283b068981791
13581452729596a
14244d04dd06565
151022dde0bb54d
hex7727a915bf1d

131012224204573 has 2 divisors, whose sum is σ = 131012224204574. Its totient is φ = 131012224204572.

The previous prime is 131012224204553. The next prime is 131012224204579. The reversal of 131012224204573 is 375402422210131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126576495386884 + 4435728817689 = 11250622^2 + 2106117^2 .

It is a cyclic number.

It is not a de Polignac number, because 131012224204573 - 241 = 128813200949021 is a prime.

It is a super-2 number, since 2×1310122242045732 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131012224204579) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112102286 + 65506112102287.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112102287).

Almost surely, 2131012224204573 is an apocalyptic number.

It is an amenable number.

131012224204573 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224204573 is an equidigital number, since it uses as much as digits as its factorization.

131012224204573 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80640, while the sum is 37.

The spelling of 131012224204573 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred four thousand, five hundred seventy-three".