Base | Representation |
---|---|
bin | 1011111010100101111000… |
… | …1010010000101101111111 |
3 | 1201101110120020121101201122 |
4 | 2332221132022100231333 |
5 | 3204122304340013043 |
6 | 43510342202501155 |
7 | 2521350456406613 |
oct | 276513612205577 |
9 | 51343506541648 |
10 | 13101230001023 |
11 | 41a122287286a |
12 | 15771335047bb |
13 | 7405962648c8 |
14 | 334162585343 |
15 | 17abd6886368 |
hex | bea5e290b7f |
13101230001023 has 2 divisors, whose sum is σ = 13101230001024. Its totient is φ = 13101230001022.
The previous prime is 13101230001019. The next prime is 13101230001029. The reversal of 13101230001023 is 32010003210131.
It is a weak prime.
It is an emirp because it is prime and its reverse (32010003210131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13101230001023 - 22 = 13101230001019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13101230000992 and 13101230001010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13101230001029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550615000511 + 6550615000512.
It is an arithmetic number, because the mean of its divisors is an integer number (6550615000512).
Almost surely, 213101230001023 is an apocalyptic number.
13101230001023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101230001023 is an equidigital number, since it uses as much as digits as its factorization.
13101230001023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 13101230001023 its reverse (32010003210131), we get a palindrome (45111233211154).
The spelling of 13101230001023 in words is "thirteen trillion, one hundred one billion, two hundred thirty million, one thousand, twenty-three".
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