Base | Representation |
---|---|
bin | 1011111010100101111000… |
… | …1110000111000100110111 |
3 | 1201101110120022111122220222 |
4 | 2332221132032013010313 |
5 | 3204122310114310403 |
6 | 43510342240244555 |
7 | 2521350501111545 |
oct | 276513616070467 |
9 | 51343508448828 |
10 | 13101231010103 |
11 | 41a12233a1a15 |
12 | 157713391075b |
13 | 740596528cb2 |
14 | 334162768d95 |
15 | 17abd69d5338 |
hex | bea5e387137 |
13101231010103 has 2 divisors, whose sum is σ = 13101231010104. Its totient is φ = 13101231010102.
The previous prime is 13101231010069. The next prime is 13101231010117. The reversal of 13101231010103 is 30101013210131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13101231010103 - 232 = 13096936042807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13101231010003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550615505051 + 6550615505052.
It is an arithmetic number, because the mean of its divisors is an integer number (6550615505052).
Almost surely, 213101231010103 is an apocalyptic number.
13101231010103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101231010103 is an equidigital number, since it uses as much as digits as its factorization.
13101231010103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13101231010103 its reverse (30101013210131), we get a palindrome (43202244220234).
The spelling of 13101231010103 in words is "thirteen trillion, one hundred one billion, two hundred thirty-one million, ten thousand, one hundred three".
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