Base | Representation |
---|---|
bin | 1011111010100110001001… |
… | …1001111001110010000011 |
3 | 1201101110202012121012102011 |
4 | 2332221202121321302003 |
5 | 3204122431102211433 |
6 | 43510353225033351 |
7 | 2521352312600641 |
oct | 276514231716203 |
9 | 51343665535364 |
10 | 13101301210243 |
11 | 41a1259a8a364 |
12 | 1577153325857 |
13 | 7405a7c3793c |
14 | 33416bc00191 |
15 | 17abdcc503cd |
hex | bea62679c83 |
13101301210243 has 2 divisors, whose sum is σ = 13101301210244. Its totient is φ = 13101301210242.
The previous prime is 13101301210177. The next prime is 13101301210367. The reversal of 13101301210243 is 34201210310131.
It is a weak prime.
It is an emirp because it is prime and its reverse (34201210310131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13101301210243 is a prime.
It is not a weakly prime, because it can be changed into another prime (13101301210843) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550650605121 + 6550650605122.
It is an arithmetic number, because the mean of its divisors is an integer number (6550650605122).
Almost surely, 213101301210243 is an apocalyptic number.
13101301210243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101301210243 is an equidigital number, since it uses as much as digits as its factorization.
13101301210243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 13101301210243 its reverse (34201210310131), we get a palindrome (47302511520374).
The spelling of 13101301210243 in words is "thirteen trillion, one hundred one billion, three hundred one million, two hundred ten thousand, two hundred forty-three".
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