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34201210310131 is a prime number
BaseRepresentation
bin1111100011011000101101…
…11111011100110111110011
311111002121022011002021021211
413301230112333130313303
513440323034314411011
6200423452532300551
710126645605665314
oct761542677346763
9144077264067254
1034201210310131
11a996719661827
123a04510171757
13161121121b097
148634c142260b
153e49ba5cdb21
hex1f1b16fdcdf3

34201210310131 has 2 divisors, whose sum is σ = 34201210310132. Its totient is φ = 34201210310130.

The previous prime is 34201210310021. The next prime is 34201210310159. The reversal of 34201210310131 is 13101301210243.

It is a strong prime.

It is an emirp because it is prime and its reverse (13101301210243) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34201210310131 - 215 = 34201210277363 is a prime.

It is a super-2 number, since 2×342012103101312 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (34201210310161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17100605155065 + 17100605155066.

It is an arithmetic number, because the mean of its divisors is an integer number (17100605155066).

Almost surely, 234201210310131 is an apocalyptic number.

34201210310131 is a deficient number, since it is larger than the sum of its proper divisors (1).

34201210310131 is an equidigital number, since it uses as much as digits as its factorization.

34201210310131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 34201210310131 its reverse (13101301210243), we get a palindrome (47302511520374).

The spelling of 34201210310131 in words is "thirty-four trillion, two hundred one billion, two hundred ten million, three hundred ten thousand, one hundred thirty-one".