Base | Representation |
---|---|
bin | 1011111010100110001001… |
… | …1101010101101101101011 |
3 | 1201101110202021021222010121 |
4 | 2332221202131111231223 |
5 | 3204122431320023313 |
6 | 43510353300224111 |
7 | 2521352323342204 |
oct | 276514235255553 |
9 | 51343667258117 |
10 | 13101302111083 |
11 | 41a125a54515a |
12 | 157715369b037 |
13 | 7405a8191994 |
14 | 33416bd965ab |
15 | 17abdcd7c28d |
hex | bea62755b6b |
13101302111083 has 2 divisors, whose sum is σ = 13101302111084. Its totient is φ = 13101302111082.
The previous prime is 13101302111047. The next prime is 13101302111113. The reversal of 13101302111083 is 38011120310131.
It is a strong prime.
It is an emirp because it is prime and its reverse (38011120310131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13101302111083 is a prime.
It is not a weakly prime, because it can be changed into another prime (13101302112083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550651055541 + 6550651055542.
It is an arithmetic number, because the mean of its divisors is an integer number (6550651055542).
Almost surely, 213101302111083 is an apocalyptic number.
13101302111083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101302111083 is an equidigital number, since it uses as much as digits as its factorization.
13101302111083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 13101302111083 in words is "thirteen trillion, one hundred one billion, three hundred two million, one hundred eleven thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.112 sec. • engine limits •