Base | Representation |
---|---|
bin | 111101000000011111… |
… | …1101111011111100011 |
3 | 110112011112110202101001 |
4 | 1322000333233133203 |
5 | 4121303340242011 |
6 | 140104151452431 |
7 | 12315425633404 |
oct | 1720077573743 |
9 | 415145422331 |
10 | 131013212131 |
11 | 506205a742a |
12 | 21484087117 |
13 | c47ba89639 |
14 | 64abc959ab |
15 | 361bca47c1 |
hex | 1e80fef7e3 |
131013212131 has 2 divisors, whose sum is σ = 131013212132. Its totient is φ = 131013212130.
The previous prime is 131013212117. The next prime is 131013212171. The reversal of 131013212131 is 131212310131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131013212131 - 231 = 128865728483 is a prime.
It is a super-2 number, since 2×1310132121312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131013212099 and 131013212108.
It is not a weakly prime, because it can be changed into another prime (131013212171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506606065 + 65506606066.
It is an arithmetic number, because the mean of its divisors is an integer number (65506606066).
Almost surely, 2131013212131 is an apocalyptic number.
131013212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131013212131 is an equidigital number, since it uses as much as digits as its factorization.
131013212131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 131013212131 its reverse (131212310131), we get a palindrome (262225522262).
The spelling of 131013212131 in words is "one hundred thirty-one billion, thirteen million, two hundred twelve thousand, one hundred thirty-one".
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